Adam Borowski <kilobyte@???> writes:
> On Tue, Jun 21, 2016 at 03:13:21PM +0200, Irrwahn wrote:
>> On Tue, 21 Jun 2016 14:42:46 +0200, Edward Bartolo wrote:
>> [...]
>> > if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z')) {
>> [...]
>> You should *never* assume that the latin letters occur in
>> the execution character set in ascending consecutive order.
>> (Though similar *is* guaranteed for the digits '0' to '9'!)
>
> Not really -- assuming ASCII is like assuming 8-bit bytes[1].
The UNIX(*) standard meanwhile mandates 8-bit bytes,
3.84 Byte
An individually addressable unit of data storage that is exactly
an octet, used to store a character or a portion of a character;
see also Character. A byte is composed of a contiguous sequence
of 8 bits.
http://pubs.opengroup.org/onlinepubs/9699919799/basedefs/V1_chap03.html
The C standard as mandates continuous encoding of '0' .. '9':
In both the source and execution basic character sets, the
value of each character after 0 in the above list of decimal
digits shall be one greater than the value of the previous.
[ISO/IEC 9899:1999 (E), 5.2.1|3]
Lastly, if the target system is Linux (as here), one can safely assume
that EBCDIC won't be used.
None of this matter anyhow for solving algorithm exercises in an
entry-level book about a programming language.
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Re: [DNG] [OT] [Re: Studying C as t…
